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Factor Completely: 12a^3d^2 − 6ad^3. Prime 6a^3d^3(2a − d) 6ad^2(2ad − d) 6ad^2(2a^2 − d)
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any guesses for this one ?
lol b
common factor is \(6ad^2\) as as start
no that won't work because if you multiply out you get \(6a^2d^3\) as the first term
i think if you check the last one it will work
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oh okay thanks
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