For qps find the sine, cosine, and tangent of .
4 years ago
sine <p = opposite side / hypotenuse cosine <p = adjacent / hypotenuse tan <p = opposite / adjacent4 years ago
ok4 years ago
clue: hypotenuse = QP = 244 years ago
i dont know how to do this stuff, never mind4 years ago
well the side opposite angle p = QR = 5 so the sine of <p = 5 /244 years ago