hey :)

Identify the vertex, focus, and directrix of the parabola with the equation x^2 – 6x – 8y + 49 = 0

Question

hey :) 

Identify the vertex, focus, and directrix of the parabola with the equation x^2 – 6x – 8y + 49 = 0

anonymous · Answer

@experimentX hey :) i'm new to this...but do you know how to do this??

experimentx · Answer

do you know the standard equation of Parabola?

anonymous · Answer

ughh, is it ax^2+bx+c

experimentx · Answer

no google it

anonymous · Answer

y - k = a(x - h)^2?

experimentx · Answer

yeah ... can you find directrix, focus and vertex from it?

anonymous · Answer

hm, i don't think so..i get so confused on this stuff :(

experimentx · Answer

do you know what these terms mean?

anonymous · Answer

yeah, sort of

anonymous · Answer

directrix is a line that the parabola that curves away from

experimentx · Answer

not just that ...

anonymous · Answer

i forgot :/ but i know first with have to put the equation into standard form (y - k)² = 4p(x - h) ....sooo

experimentx · Answer

anonymous · Answer

it's 14 minutes longg, but okay :)

experimentx · Answer

anonymous · Answer

ooh, i remember this stuff now! kindaa :)

anonymous · Answer

but how do i put 6x – 8y + 49 = 0  into like standard form equation

anonymous · Answer

x2 – 6x – 8y + 49 = 0 **

anonymous · Answer

i don't have that much time to do this :(

experimentx · Answer

no ... |dw:1362692616831:dw|