solve by factoring x^2+8x=20? Can anyone show me how to do this, i'm struggling!
i know x=4, but i don't remember how to work this?
good to know you'restruggling eith a question...... x^2+8x-20=0 x^2+10x -2x-20=0 x(x+10)-2(x+10)=0 (x+10)(x-2)+0 x=-10 or 2
x=2*
its=0
not+0
Ohh okay, i see what i was doing wrong, thanks(: Would you mind helping with one more?
@Meinme
yeah feel free
Okay, this one is: Solve by quadratic formula 5x^2 + 2x - 7 = 0
b^2-4ac= 4+140=144 by quadratic formula we have |dw:1362693495342:dw|
ans is 1 or -1.4
wait, how do you know to put -2 +- sqrt 144 over 10? @meinme
its formula
okay, i just dont understand how you get those numbers, from the numbers i gave you? does that make sense,
yeah do u know the formula of finding x in quadratic?
yes
{-b+-sqrt(b^2-4ac}/2a
right, so how do you determine which is a, b, and c...
general quadratic equation is ax^2+bx+c=0 now compare your equation youll get a, b and c
Ohh, okaay, i see. Thank you so much.
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