Question

Need help with: ax^2 + bx + c
4x^2 - 6x + 1 = 0
I couldn't figure out the answer so I looked it up on Wolfram Alpha and it said the answers were
x = 1/4, 3 - √5, and 0.19098
and
x = 1/4, 3 + √5, and 0.13090

But when I looked it up some more it said that
3 - √5 = 6.708
3 + √5 - 5.236

I'm supposed to be finding the x decimals so I can graph them and make a parabola, but I'm not sure how to find the correct answer.

Answer 1

Welll you use the quadratic formula

-b ± √(b² - 4ac) all over 2a

the a b and c are the coefficients

so

4x^2 - 6x + 1

6 ± √((-6²) - 4(4)(1)) all over 2(4)

so 6 ± √36 - 16 all over 8

6 ± √20 all over 8

6 ± 2√5 all over 8

so your 2 points will be

6 + 2√5 all over 8 = 1.309

and

6 - 2√5 all over 8 = .19098

could be wrong but

Answer 2

Oh okay, I get it now! Thanks so much.