Question

if tan^3 theta -1/ tan theta - sec^2 theta -1 = 0, find cot

Answer 1

\[\frac{(\tan \theta-1)(\tan ^2\theta+\tan \theta+1)}{\tan \theta-1}-\sec ^2\theta-1=0\]

Answer 2

\[\tan ^2\theta+\tan \theta+1-\sec ^2\theta-1=0\]

Answer 3

still confused :(

Answer 4

What are you confused about? Do you know how to factor a^3-b^3?

Answer 5

how am i suppose to find cot?

Answer 6

Do you understand so far?

Answer 7

sort of, i dont really have much time left before i need to turn in my hw.

Answer 8

\[\sec ^2\theta+\tan \theta-\sec ^2\theta-1=0\]

Answer 9

\[\tan \theta=1\]

Answer 10

\[\frac{1}{\tan \theta}=1\]

Answer 11

\[\cot \theta=1\]

Answer 12

thank you! i just struggle with breaking down equations.

Answer 13

yw