Question

What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units?

Answer 1

so using this given information and letting the length by l, and width w

56 = 2l + 2w

making w the subject

w = 1/2(56 - 2l)

or

w = 28 - l (equation 1)

now the area

96 = lw

substitute equation 1 into the area formula

96 =l(28 -l)

you need to distribute and have to solve a quadratic.

Hope this makes some sense.

Answer 2

Thanks