Question

Log5(x+2)+log5(2x-1)=2

Answer 1

\[\log_{5}(x+2) + \log_{5}(2x-1)=2\]
As \[\log_{a}b+\log_{a}c=\log_{a}bc\]
\[\log_{5}[(x+2)(2x-1)]=2\]
\[[(x+2)(2x-1)]=5^{2}\]
now simplify.

Answer 2

Do I solve regularly or distribute the parenthesis to each other