Question

Can someone help me with this

Answer 1

with what ?

Answer 2

Factor completely 56a^2b^3 - 35ab

Answer 3

What

Answer 4

The GCD of 56 and 35 is 7,
the GCD of a^2b^3 and ab is ab,
so, the common factor is 7ab
therefore, it is 7ab(8ab^2 - 5)

Answer 5

Ok now how do I solve 2x^3 + 10x^2 + 4x + 20

Answer 6

2x^3 + 10x^2 + 4x + 20 = 2(x^3 + 5x^2 + 2x + 10) = 2(x^2+2)(x+5)
any else :)

Answer 7

Can it be the other way around

Answer 8

actually, use the long division or synthetic division

Answer 9

I don't get it does x become 2x