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lim x approaches infinity of ln (e^x -1) - x
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\[\lim_{x \rightarrow \infty} e ^{x} - 1 - x\]
is that the ques?
isn't this obvious?? when x grows every large ... e^x completely dominates -1
no this is not the question, it is the limit of; ln(e^x +1)-x
what ever there is e^x+1 =e^x as x goes very large.
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the answer is 0 ... just by looking!!
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