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OpenStudy (mathsolver):
Given that log6=log3+log2, express log5 in terms of log2 and log3
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OpenStudy (anonymous):
don't log5 is breakable into 2 and 3, since 5 is a prime.
OpenStudy (anonymous):
think*
OpenStudy (mathsolver):
That's what I thought :( that was pulled straight from an exam paper though. Do you have any idea how to solve it?
OpenStudy (anonymous):
no idea
OpenStudy (raden):
log 5 = log (10/2) = log 10 - log 2 = 1 - log 2 = (log 3/log 3) - log 2
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