Question

Algebra 2 help, Please?? Multiple choice

Answer 1

\[\frac{ x^2+4x-5 }{ 5x^2-8x+3 }\times \frac{ 20x-12 }{ x^2-6x-55 }\]

Answer 2

\[A. \frac{ 4 }{ x+5 }\]

Answer 3

\[B. \frac{ 4(x-1) }{ x+5 }\]

Answer 4

\[C. \frac{ 4 }{ x-11 }\]

Answer 5

\[D. \frac{ 4(x+5) }{ x-11 }\]

Answer 6

You can simplify that to\[\frac{ (x^2+4x-5)(20x-12) }{ (5x^2-8x+3)(x^2-6x-55) }\]Do you know how to simplify from there?

Answer 7

Foil??

Answer 8

Yes, and then you can simplify binomials that are both in the bottom and top of the fraction.