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Write the expression as a single natural logarithm. 3ln3 + 3lnc A. ln(27 + c3) B. ln9c3 C. ln27c D. ln27c3
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\[aln(b) = \ln(b^a)\]
\[\ln(a) + \ln(b) = \ln(ab)\]
\[3 \ln 3 +3 \ln c =\ln (3)^3+ \ln (c)^3=\ln 27+\ln c^3=\ln(27c^3)\]
\[\ln a + \ln b = \ln(ab)\]
thanks
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:) i am sorry i wasnt supposed to solve the whole thing but i just did it , my bad :(
its fine thank you i understand it
:D
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