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Mathematics 6 Online
OpenStudy (anonymous):

HELp=

OpenStudy (anonymous):

OpenStudy (nubeer):

\[\frac{ AK }{ AX } = \frac{ DN }{ DX }\] You have the values for all terms except DN. Just plug in values you will get DN

OpenStudy (anonymous):

would it be 1.3cm ?

Directrix (directrix):

I am using similar triangles. Triangle DXN ~ Triangle AXK by AA Postulate. Both triangles share angle X and both triangles have a right angle. Corresponding sides of similar triangles are in proportion so...

Directrix (directrix):

DX/AX = DN/AK 2.2 / ( 6 + 2.2 ) = DN / 4.9 We need to solve this and see what DN may be.

Directrix (directrix):

@Megan_xoxo would it be 1.3cm ? Yes, that is what the proportion yields.

Directrix (directrix):

Question?

OpenStudy (anonymous):

thanks :)

Directrix (directrix):

Glad to help.

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