[6.01] Select the system of equations that corresponds to the given graph.
-2x - y = 4 2x + y = -2 -8x + 4y = -16 -4x + 2y = -8 x + 2y = 4 2x - 4y = 8 2x + 3y = 6 3x + 2y = 4
???
from this graph you get that when x=4 y=0 and when x=0 y=-2 and when x=0 y=2
now you need check these roots to what equations coresponde,are right ok ?
-2x - y = 4 2x + y = -2 -8x + 4y = -16 -4x + 2y = -8 x + 2y = 4 2x - 4y = 8 2x + 3y = 6 3x + 2y = 4 i can choose from these
-2x - y = 4 2x + y = -2 -8x + 4y = -16 -4x + 2y = -8 x + 2y = 4 2x - 4y = 8 or 2x + 3y = 6 3x + 2y = 4
yes from these you need to chose it
is it the 1st one?
are you sure ?
when y=0 rsulte x=4
1. will be x+2y=4
because here you see if you check it that for y=0 result x=4 yes ?
yes
you need getting again two ok ?
for x=0 y=2 and for x=0 y=-2
ok...?
the second one will be for y= -2
and for y=2 can you get it ?
x+2y=4
so and with this you have got all ok ?
do you understand it why are these equations right for these points ?
yes but i dont get which choice is right
so from this graph you see there that for these intersection points of thses lines with axe x and y there are these points of intersection for x you see 4 and for y 2 and -2 yes ?
so after this you just need to get these equations for what has like roots these points of intersection 2,-2 and 4
ok ?
ok
so than good luck bye
you can just solve both of the line equations y= mx + b
use the points (0,2) and (4,0) and (4,0) and (0,-2) so for the first y=mx+b you get y = (rise/run) x + b y= ((0-2)/(4-0))x+b y=-1/2x+b now substitute the point ( 4,0) and get the b (0)=-1/2(4)+b) b = 2 so first equation is y = -2x + 2 or y+1/2x=2 or 2y+x=4 you can similarly solve for the 2nd equation and get y= 1/2(x) - 2 or 2y-x=-4 or -4y+2x=8 if u multiply by -2
when i mean or thats just multiplying both sides of the equation by a constant so theyre all equal
i hope that makes sense
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