Question

Solve 4x^2+8x–252=0 by graphing

Answer 1

You should draw the graph.

x = 0 corresponds to y = -252
Do more!

Answer 2

4x^2+8x–252=0-> 0=4(x+1)^2-256
Vertex- x+1=0, x=-1
Axis of symmetry- -1
Domain- All real numbers
Range- y>=4

Right?

Answer 3

Oops, forgot to finish the vertex...
Vertex- x+1=0, x=-1
y=4(-1+1)^2-256
y=4(0)^2-256
y=4(0)-256
y=-256
(-1,-256)

Answer 4

That's pretty good. There are a couple of refinements.

1) The Axis of Symmetry should be expressed as an equation of a line. x = -1
2) The Range is no good. For a parabola, this would always be a reference to the vertex. y >= -256

Answer 5

Thank you (: