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Find the derivative of g(x)=3x^3-8x^2+5x-9
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g(x) = 3x^3 - 8x^2 + 5x - 9 g(x) = 9x^2 - 16x + 5 (this is the answer)
ok I got the same thing thanks.
but wait where didi the 9 go
Because d/dx (-9) = 0. That's why...
oh ok
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thanks
I hope you understand how the derivative works. If not, then I suggest you to read this: http://www.cliffsnotes.com/study_guide/Differentation-Rules.topicArticleId-39909,articleId-39879.html
ok thanks
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