Question

4x-5=16x^3-20x^2

Answer 1

Equation:
\[16x^3 - 20x^2 - 4x + 5 = 0\]
Factor by grouping:
\[[16x^3 - 20x^2] - [4x - 5] = 0\]
\[4x^2 (4x - 5) - 1 ( 4x-5) = 0\]
Which is equivalent to
\[(4x-5) (4x^2 - 1) = 0\]
Now solve.