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How do I solve this by completing the square: x2 + 8x = -3.
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\[ (x+d)^2 = x^2+2dx+d^2 \\\ 2d = 8 \implies d = 4\implies d^2=16\\ (x+4)^2-16 = -3\\ (x+4)^2=13 \]
is that the final answer?
Do I win a million dollars?
I did the same thing but it's not in the choices :/
What are the choices?
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A. -3 and -5 B. -4 - √13 and -4 + √13 C. -4 - √19 and -4 + √19 D. 4 - √13 and 4 + √13
\[\begin{array}{ccr} (x+4)^2&=&13\\ |x+4| &=& \sqrt{13}\\ x+4 &=& \pm \sqrt{13} \\ x &=& -4 \pm\sqrt{13} \end{array} \]
I salute you sir
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