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16x^2-240-32=0? Can someone check my answer? What am I doing wrong? I got( -1,2)
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16(x^2-15-2)=0 (x+1)(x-2)
You factored the equation incorrectly.
how so?
(x+1)(x-2)=x^2-2x-2.
you'll have to use the quadratic equation for this one I believe, as b^2-4ac is not a perfect square.
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*formula I mea
I did- see this is what I had 16x^2-240-32x=0 then 16(x^2-15-2)=0 then divid each side by 16 then this is where I had problems
what do you mean exactly? that was correct, but 16(x^2-15-2)=0 x^2-15-2=0 at this point you factored the equation incorrectly. You must use the quadratic equation for this one.
Thanks for your help. The answer was actually 3, -5
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