Question

Help please!

What are the vertices, foci, and asymptotes of the hyperbola with the equation 16x2 – 4y2 = 64?

Answer 1

Get it in the right form by dividing each term by 64

Answer 2

is y=(sqrt)((x-2)(x+2)) right?

Answer 3

\[\frac{16x^2}{64}-\frac{4x^2}{64}=\frac{64}{64}\]

Answer 4

...or \(4y^{2}\)...

Answer 5

\[\frac{x^2}{4}-\frac{y^2}{16}=1\]

Answer 6

Does that help?

Answer 7

Yes! Thanks a bunch! I was completely stuck.

Answer 8

a=2, b=4

Answer 9

yw

Answer 10

So what is the problem?