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If I have sqrt((x^-1+2+x)/4) how does it "turn into a square" so I can then sqrt it and then finish my integration?
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factor out a 1/x
\(\huge \dfrac{((x^{-1/2})^2+2\times x^{-1/2}x^{1/2}+(x^{1/2})^2)}{2^2} \\ = \huge (\dfrac{x^{-1/2}+x^{1/2}}{2})^2\)
so, \(\huge \sqrt{(x^{-1}+2+x)/4}=(x^{-1/2}+x^{1/2})/2\) can you integrate now ?
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