Question

h=12+94t-16t^2 factor the right side so i take the bggest common factor which is 2 and 2(6+47t-8t^2) and then.. ?

Answer 1

now you need to factor the quadratic

here is a process

for a quadratic

\[ax^2 + bx + c\]

multiply a and c -8 * 6 = -48

find the factors that add to 47..... 48, -1

then set up

(at + factor1)(at + factor 2)
-------------------------
a

in your question its

(-8t + 48)(-8t - 1)
------------------
-8

remove a common from the 1st binomial

-8(t - 6)(-8t - 1)
-----------------
- 8

cancel the common factor which leaves

h = 2(t - 6)(-8t - 1)

as the factored form. or you can take -1 as a common factor and write it as

h = -2(t - 6)(8t + 1)

which ever you choose.

Answer 2

omg this is very helpful!!! i think im getting it noww!! thank you so much!!