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In circle O, PA and PB are are tangents. (The figure is not drawn to scale.) Find m BOD for m AOP = 64. Explain your reasoning.
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ok... thia requires a congruency proof in simple terms in triangles OBP and OAP tangents from an external point are equal PB = PA OA is a common side bO = AO equal radii... therefore congruent then angle angle AOP = BOP..... corresponding angles in congruent triangles... so BOD is supplementary to BOP BOD = 180 - 64 hope this helps
sorry for the abbreviated nature of the proof.
thank u so much
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