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Mathematics 18 Online
OpenStudy (anonymous):

Factor completely 50a2b5 – 35a4b3 + 5a3b4 5a2b3(10b2 – 7a2 + ab) 10b2 – 7a2 + ab a2b3(50b2 – 35a2 + 5ab) 5(10a2b5 – 7a4b3 + a3b4)

OpenStudy (nurali):

50a2b5 – 35a4b3 + 5a3b4 5a2b3(10b2 – 7a2 + ab)

OpenStudy (anonymous):

I agree with Nurali :)

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