Question

The tangent to the curve y = x3 at (1,1) meets the graph at a second point. Having trouble getting the second point, without just resorting to guessing..

Answer 1

define the tangent line at the point 1,1

Answer 2

then equate where the tangent line and the curve are equal

Answer 3

you should have something like:

y=x^3 and y=mx+b

therefore the points in common are when:

x^3 = mx+b