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Find the cost to rent a car for 5 days at $27.50 per day and $ .16 per mile if the car is driven 378 miles.
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algebraically represent $27.50 per day
@stamp what do you mean?
how do you algebraically compute the cost for a charge of 27.50 per day?
i know that if i drive 60 miles per hour for 1 hour, i have driven 60*1 = 60 miles or if I have driven 60 miles per hour for 2 hours, I have driven 60*2 = 120 miles in otherwords, at 60 miles per hour, miles driven = 60*h m = 60h
how do I solve for cost c if i charge 27.50 per day
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You would take 27.50 times 5?
algebraically where is your variable
C= cost? Im not sure what you are saying. sry.
c = 27.50d
|dw:1363033326523:dw|
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