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OpenStudy (anonymous):
[(sin^2x/cos^2x)-sin^2x]/[(sin^2x/cos^2x)sin^2)]? i got my problem this far and now im stuck.): any hints?
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OpenStudy (anonymous):
what are you supposed to do? simplify?
OpenStudy (anonymous):
verify. it all equals to 1
OpenStudy (anonymous):
try getting common denomnator
OpenStudy (anonymous):
aha! i got it:) thanks!
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