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Mathematics 13 Online
OpenStudy (anonymous):

[(sin^2x/cos^2x)-sin^2x]/[(sin^2x/cos^2x)sin^2)]? i got my problem this far and now im stuck.): any hints?

OpenStudy (anonymous):

what are you supposed to do? simplify?

OpenStudy (anonymous):

verify. it all equals to 1

OpenStudy (anonymous):

try getting common denomnator

OpenStudy (anonymous):

aha! i got it:) thanks!

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