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Exponents: write with no denominaators. ax^2/b^3y
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Remember that 1/a^b=a^(-b)
yes
Now move the expressions in the denomintor up to the numerator using that
ax^2&b^-1y?
What happened to be being cubed? Why didn't the exponent on y not change when bringing it up the numerator?
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ug ok ax^2*b^-#y
B^-3y,,,
Watch that shift key. You still need to negate the exponent on y
ax^2*b^-3-y
Try using parenthesis to clarify. Why is y being subtracted now?
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i thought i had to negate it
Not negate y. But the exponent of y
Y^-1???
Yes.
Because y^(-1)=1/y, right.
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ax^2*b^-3^-3-3y-1
i think i get it,,, maybe
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