13. A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = â€“16tÂ² + 148t + 30. How long does it take the boulder to reach its maximum height? What is the boulderâ€™s maximum height? Round to the nearest hundredth, if necessary. (1 point) A) 9.25 s; 30 ft B) 4.63 s; 640.5 ft C) 4.63 s; 1,056.75 ft D) 4.63 s; 372.25 ft 16. Solve the equation using the Zero Product Property. (2x â€“ 4)(2x â€“ 1) = 0 (1 point) A) 2, â€“1over2 B) 2, 1over2 C) â€“2, 2 D) â€“2, 1over2

1.) 32t + 148 = 0 148 = 32t 4.625 = t t â‰ˆ 4.63 h = -16 â€¢ (4.625)^2 + 148 â€¢ 4.625 + 30 = 372.25 4.63 s; 372.25 ft ANSWER: D.) 2.) 2x - 4 = 0 and 2x - 1 = 0 x = {4/2, Â½} x = {2,Â½} ANSWER: B.)

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http://www.jiskha.com/display.cgi?id=1363045983 this explains it pretty well

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