cos(9pi/2-pi/6)
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Knowing cos(pi/3) = 1/2. We let the denominators in your function be some pi/6. 27pi/6 - pi/6 = 26pi/6, which simplifies to 13pi/3. Since pi/3 = 1/2. 13pi/3 = 13/2.
13/2 is not correct :(
Ahh how silly of me, 1/2. I'm forget this is a unit circle.
i kn01 cos(pi/6)=\[\sqrt{3}\]/2 and sin(pi/6)=1/2
ok let me try that (:
1/2 is correct! can you explain how you knew that?
Yes, 13pi/3 would be right. Unit circle in radians ranges from (0, 2pi) 3 goes into 13 4 times with pi/3 remaining which = 1/2
It uses some trig and pre-calculus knowledge. http://en.wikipedia.org/wiki/Unit_circle
this is homework for my precal class and its the first time i have ever taken precal and is ridiculously hard!
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