Question

Prove that..
@yrelhan4 @Mashy

Answer 1

\[\LARGE U=\sqrt{2g(H+\frac{R^2}{16H})}\]

Answer 2

u=projectile wala..

Answer 3

\[H = \frac{u^2\sin^2( \theta)} {2g}... R = \frac{u^2\sin(2 \theta)}{g}\]

Answer 4

thanks! :D

Answer 5

@Mashy PLEASE GIVE MY EXAM TOMORROW!! DX

Answer 6

??

Answer 7

ok
;p