Factor completely: 14bx2 − 7x3 − 4b + 2x

(2b + x)(7x2 + 2)

(2b − x)(7x2 − 2)

(2b + x)(7x2 − 2)

prime

Question

Factor completely: 14bx2 − 7x3 − 4b + 2x

(2b + x)(7x2 + 2)

(2b − x)(7x2 − 2)

(2b + x)(7x2 − 2)

prime

jiteshmeghwal9 · Answer

First make the system serial-wise.

(14bx^2-4b)-(7x^3+2x)

zehanz · Answer

First, split up in two parts: 
14bx2 − 7x3 − 4b + 2x =(14bx²-7x³) - (4b - 2x)
Now factor both parts indepentdently, taking out the common factors:
7x²(2b-x) - 2(2b - x)

Now, the last step: 2b-x is a common factor, so factor it out...

zehanz · Answer

@jiteshmeghwal9: I think you missed a - in the right part.

anonymous · Answer

(2b + x)(7x2 − 2) 
is that it ?

zehanz · Answer

Yes! You got it.

zehanz · Answer

Oh, no: you also missed a - sign, it is (2b - x)(7x2 − 2)

zehanz · Answer

Because 2b-x was the common factor!

anonymous · Answer

oh so its teh second choice ?

zehanz · Answer

It is!