Question

Factor completely: 14bx2 − 7x3 − 4b + 2x

(2b + x)(7x2 + 2)

(2b − x)(7x2 − 2)

(2b + x)(7x2 − 2)

prime

Answer 1

First make the system serial-wise.

(14bx^2-4b)-(7x^3+2x)

Answer 2

First, split up in two parts:
14bx2 − 7x3 − 4b + 2x =(14bx²-7x³) - (4b - 2x)
Now factor both parts indepentdently, taking out the common factors:
7x²(2b-x) - 2(2b - x)

Now, the last step: 2b-x is a common factor, so factor it out...

Answer 3

@jiteshmeghwal9: I think you missed a - in the right part.

Answer 4

(2b + x)(7x2 − 2)
is that it ?

Answer 5

Yes! You got it.

Answer 6

Oh, no: you also missed a - sign, it is (2b - x)(7x2 − 2)

Answer 7

Because 2b-x was the common factor!

Answer 8

oh so its teh second choice ?

Answer 9

It is!