Question

3n^2 -8n+4

Answer 1

idk lol im confuse to

Answer 2

(3n - 2)(n-2) is the original equation factored. If your solving for n, n would be 2 and 2/3

Answer 3

3n^(2)-8n+4

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (12) that add up to b (-8).In this problem -(2)/(3)*-2=(4)/(3) (which is (c)/(a)) and -(2)/(3)-2=-(8)/(3) (which is ((b)/(a)) , so insert -(2)/(3) as the right hand term of one factor and -2 as the right-hand term of the other factor.
(n-(2)/(3))(n-2)

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(3n-2)(n-2)