Please help me with areas of regular polygons ♥ Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 3-inch radius
I'm assuming they're talking about the circumradius
we have this equilateral triangle |dw:1363121879585:dw|
from the center of the triangle to the vertex is the circumradius and we know it's 3 inches |dw:1363121917495:dw|
drop a perpendicular line segment to one of the side to get this |dw:1363121964055:dw|
Doesn't that make a 30, 60, 90 triangle??
now the circumradius cuts the angle of a the equilateral triangle in half so we go from 60 degrees to 30 degrees and yes, that forms a 30, 60, 90 |dw:1363122037512:dw|
the shorter leg is half of the hypotenuse, so the shorter leg is 3/2 the longer leg is sqrt(3) times longer than the shorter leg, making the longer leg to be (3/2)*sqrt(3) units long |dw:1363122127530:dw|
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