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Mathematics 20 Online
OpenStudy (anonymous):

help please.

OpenStudy (anonymous):

with what?

OpenStudy (anonymous):

OpenStudy (anonymous):

what is "inter quartile range" does it mean the middle half?

OpenStudy (anonymous):

we can do this

OpenStudy (anonymous):

the area of that triangle on the right is 1, because the area has to be one therefore the height is \(\frac{1}{4}\)

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

how did you get height 1/4?

OpenStudy (anonymous):

i mean on the left, not on the right, but i just noticed that we do not have to even calculate it, just say if it is bigger or less than 4

OpenStudy (anonymous):

i got \(\frac{1}{4}\) as the height because the total area has to be one, and the area of a triangle is \(\frac{1}{2}bh\) in this case the base is 8 so the height must be \(\frac{1}{4}\)

OpenStudy (anonymous):

it doesn't matter anyway, because you don't actually have to compute it, you just have to say if it is larger or smaller than 4 and it is clearly smaller

OpenStudy (anonymous):

this is more than half the area |dw:1363143091389:dw|

OpenStudy (anonymous):

for the one on the right the interquartile range will be larger than 4, because the area between 2 and 6 is clearly less than half the total area

OpenStudy (anonymous):

this is less than half the area |dw:1363143276106:dw|

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