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OpenStudy (anonymous):
Suppose that a population of measurements is normally distributed with mean μ and standard deviation σ. (Round your z value to 2 decimal places and the remaining answers to 3 decimal places.) Write an expression (involving μ and σ) for a tolerance interval containing 98 percent of all the population measurements.
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Directrix (directrix):
How are we going to get the z-score without the standard deviation and mean of the population?
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