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solve 5x^2-11x+3=0
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I cant find out what adds to - 11 and multiplys to 3
it can't be solved through factorization method so u have to use the quadratic formula\[\Huge{x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}}\]
here b=-11,a=5, c=-3 put the values & solve :)
oh ok thanks
Btw how would i solve 8x-7-x^2=0?
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do i rearrange it?
Yes
how would i rearrange it?
put the x^2 on the front. -x^2+8x-7 The factor out the negative. -(x^2-8x+7) Then factor and solve
x = 7 or 1?
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is (x-7)(x-1)=0 the correct step before the answer?
Yup, that's right
oh so it doesnt matter if they have the same sign?
No
ok thanks
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