Find the general solution of the differential equation:
\[\frac{ dr }{ dp }=4\sin p\]
r=
So what you can do is play with the differential as though it were a fraction and multiply both sides by "dp" to get: dr=4sinp dp Now integrate and don't forget +C
I must be doing something wrong I'm not getting the right answer and not sure where I'm going wrong
What's the right answer supposed to be?
I don't know, but nothing I've tried is right
Show me what you get when you solve the integral I just wrote out above.
I don't see an integral
dr=4sinp dp That is an indefinite integral without its fancy looking "S" shape.
so the dr stands for the "S"?
Ok i figured it out thanks
No, dr stands for infinitesimally small. What level of calculus are you in?
Given \(dr=4\sin p\;dp,\) you can antidifferentiate both sides to get \(\int dr=\int 4\sin p\;dp.\)
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