The perimeter of a rectangle is 16x^2 +12x +18/3x in inches.The length measures 2x^2 +6x +9/3x in inches. Find an expression to represent the measure of the width in inches.

Question

mertsj · Answer

Would you agree that perimeter of rectangle is 2L+2W?

anonymous · Answer

yes, p=2L+2w

mertsj · Answer

So replace P& L  with the given values and solve the resulting equation for W

mertsj · Answer

$$16x^2+12x+\frac{18}{3x}=2(2x^2+6x+\frac{9}{3x})+2W$$

mertsj · Answer

Now distribute the 2 on the right side.

anonymous · Answer

4x^2+12x+18/3+2W?

anonymous · Answer

2l +2w=16x^2 +12x +18/3x

anonymous · Answer

2w=- 2( 2x^2 +6x +9/3x)+16x^2 +12x +18/3x= 12x^2

anonymous · Answer

w= 6x^2

anonymous · Answer

very confusing, but I think I got it. Thankyou so very much

anonymous · Answer

just thought there were more steps by having to factor it first

anonymous · Answer

my answer is right isn't it?

anonymous · Answer

the answers to choose are:   x, 2x, 4x, or 6x
I got 6x

mertsj · Answer

6x^2 is the correct answer.