Can someone walk me through this problem? The area of a rectangular pool is given by the trinomial 2y^2+y-3. whats the demensions of the pool?

Question

mertsj · Answer

Are you sure there is not a typo in your post?

anonymous · Answer

sorry i mixed up 2 questions

directrix · Answer

We need to factor this:  2y^2+y-3

directrix · Answer

Two number that multiply to -6 and add to 1

directrix · Answer

2 y^2 + 1*y - 3 =

2 y^2 + 3y - 2y - 3

anonymous · Answer

my sister woke up. i wont be on until later 2 finish this

directrix · Answer

Okay. Catch you later.

directrix · Answer

2 y^2 + 1*y - 3 =

2 y^2 + 3y - 2y - 3 =

2 y^2 - 2y + 3y - 3 =

2y(y - 1) + 3(y -1) =

(y - 1)* (2y + 3) --> pool dimensions

@JaneDoe100

anonymous · Answer

Thanks! Really appreciate all the time you put into helping me...