Question

find the area of a triangle.
(A=1/2 bh)
triangle height=2x
base=2x^2

Answer 1

ok so you have

\[A = \frac{b*h}{2}\]
\[h = 2x\]
\[b = 2x^2\]
\[A = \frac{(2x^2)*(2x)}{2} = \frac{4x^3}{2} = ?\]

Answer 2

hm i think i might have calculated wrong because the answer i got isnt right. i did the 4x^3 divided by 2 but didnt get the right answer.

Answer 3

4/2 = 2

so you should get 2x^3