Question

Are my steps right so far?
What is the 32nd term of the arithmetic sequence where a1 = -34 and a9 = -122?


First term: -34
d = -88

Answer 1

d is incorrect.

Answer 2

d= a2-a1
and not a9-a1

Answer 3

to find 'd' use n'th term formula
\(a_n=a_1+(n-1)d\)
with a1=-34
n=9
a9=-122
find 'd'

Answer 4

:( where does a2 come from??

Answer 5

thats when a2 is given
here,
to find 'd' use n'th term formula
an=a1+(n−1)d
with a1=-34
n=9
a9=-122
find 'd'

Answer 6

wait in the formula you gave, is that

Answer 7

yes, on the left side of =

Answer 8

ok:) let me figure this out on my paper

Answer 9

Where do I find the "an" part?

Answer 10

for 9th term, n= 9
so, an = a9 =-122

Answer 11

ohh!!!! okay!!!!

Answer 12

now finding the common difference..

Answer 13

-88?

Answer 14

again ?

Answer 15

The common difference: -88

Answer 16

an=a1+(n−1)d
with a1=-34
n=9
a9=-122
find 'd'

-122 = -34 + 8d
-88= 8d
d=-11
is what i get.

Answer 17

-122 - -34 = -88

Answer 18

how did you get 8d?

Answer 19

.....(n-1)*d
n=9
.....(9-1)*d
......8d

Answer 20

huh?? i am so confused by that

Answer 21

how did we get n - 1 in the first place?