Question

help?

Answer 1

10. y = x² – 2x – 2
y = 4x + 5 (1 point)
(–1, 1) and (–7, –23)
(–1, 1) and (7, 33)
(–1, 33) and (7, 1)
no solution

Answer 2

we could just plug in our x's and y's and see if the equations are true....(x,y)

Answer 3

or you could use a formula :
Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\] \[ \\\ {b^2-4ac}=...?\]
if \( \\\ {b^2-4ac}=...?\) is positive, then there is a solution
if \( \\\ {b^2-4ac}=...?\) is negative, then there is no solution