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4y/xy - 2x/xy^3
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\[\frac{ 4y }{ xy } - \frac{ 2x }{ xy ^{3} }\]
yes i really need help with that problem
if you square the equation of the left you will have common denominators
whats the answer?
well you need to know how to do it, not just the answer.
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tru
so back to what i said, if you square the first part you will have common denominators.
so if you square it you would get 16
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