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Factor the trinomial 3x^2 + 17x - 6
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3x^2 - 17x - 6 = ( 3x + 1)( x - 6)
im hoping uvkno the step??
Not really....
3x stays the same u kno that rite
3-2 is 1 u add
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cancel out the 17
and the that leave u with x-6
how do you know to subtract 3-2?
Factors of 3 1, 3 Factors of -6 1, -6 -1, 6 2,-3 -2,3 Which combination produces +17 in the middle? 3*3 = 9 1*2 = 2 Okay, all the 2-3s are out. We're down to this: (x + 1)(3x - 6) = ?? (x - 1)(3x + 6) = ?? Which one works?
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Good lord, I am lost.......
Just enumerate the possibilities. In this case, there are only four. Simply try them out!
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