Question

The sides of a right triangle form a primitive Pythagorean triple. If its semi perimeter is 120, find its area.

Answer 1

So,

A + B + C = 240 = 2*S

\(A^{2} + B^{2} = C^{2}\)

\(Area = \sqrt{S\cdot(S-A)\cdot(S-B)\cdot(S-C)}\)

Anything looking familiar?

Answer 2

What about AB/2 = Area?

Answer 3

So much information! How could you NOT find a solution?!

Answer 4

I know this looks easy and I got 2400, but correct answer is 840... I just don't understand...

Answer 5

I can see that A= 80, B= 60 and C = 100

I don't ever know where 840 comes from...