Question

find the square roots of this polynomial: (4x^2)/(y^2)-(36x)/y+81

Answer 1

\[\frac{ 4x^2 }{ x^2 }-\frac{ 36x}{ y }+81\]

Answer 2

(4x²)/(y²) - (36x)/y + 81 = 0
0 = 4(x/y)² - 36(x/y) + 81
0 = [ 2(x/y) - 9 ] [ 2(x/y) - 9 ]
......... (x/y) = 9/2

Answer 3

uinderstand?

Answer 4

wow, i never would have gotten that answer

Answer 5

not at all

Answer 6

but i have it copied so i can look at it later,,,,

Answer 7

k

Answer 8

ty!

Answer 9

np