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OpenStudy (anonymous):
(3x+3)/(x-1)=(3x+2)/(x+4)
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OpenStudy (anonymous):
get common denominators
OpenStudy (anonymous):
ok. but there is where I keep getting it wrong. Do you multiply left with x+4 and the right side with x+1?
OpenStudy (anonymous):
yupp!
OpenStudy (anonymous):
3x^2+12x+3x=3x^2-3x+2x-2 3x^2+15x+12=3x^2-x-2 3x^2+15x+12-3x^2+x+2 16x/16+14/16=7/8
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