Question

show that D(sin 2x) = 2 cos 2x

Answer 1

use chain rule

Answer 2

if h=g(x) , then
D[ f(h) ] = f'(h)*D(h)

Answer 3

D(sin2x)=D[sin2x]*D[2x]
= cos2x * 2
= 2cos2x

Answer 4

thanks